Dear Ryo san,
ave(q) = din(q) / A,
where A is the area of the integration and average. Therefore
din(q - ave(q)) = din(q) - A ave(q) = din(q) - din(q) = 0.
This makes sense to me.
integral on I and J instead of x and y as in "x=0:360@DIN, y=90S:90N@DIN"
It does brought down the value a little bit:
list test_din
VARIABLE : COMP3[X=0:360@DIN,Y=90S:90N@DIN]
FILENAME : coads_climatology.cdf
FILEPATH : /home/xbai1/miniconda2/envs/FERRET/share/fer_dsets/data/
LONGITUDE: 0E to 0E(360)
LATITUDE : 90S to 90N
TIME : 16-AUG 07:23
-90.20
I will definitely pay more attention to the difference between IJ and XY in the future.
Thank you very much and stay healthy,
Xiaoyu
I am puzzled by this issue.